Question 85967
Note that both the numerator and denominator expression will factor:
{{{(15x^2-x-2)/(3x^2-5x-2)}}} = {{{(5x-2)(3x+1)/(3x+1)(x-2)}}}
:
Cancel the (3x+1)'s and you are left with:
{{{((5x-2))/((x-2))}}}