Question 1006461
-3 -6 (4x +6) > -111
add 3 to both sides of > -111
-6 (4x +6) > -108
divide both sides of > by -6 and reverse >
4x + 6 < 18
subtract 6 from both sides of <
4x < 12
divide both sides of < by 4
x < 3
solution is all x values < 3, namely the open interval (-infinity, 3)