Question 1006405
The Standard Form equation of a line has the following formula:

{{{ax+by=c}}} where {{{a<>0}}} and {{{b<>0}}}

you are given:

{{{y-1= (5/6)(x-4)}}}.........both sides multiply by {{{6}}}

{{{6y-6= 6(5/6)(x-4)}}}

{{{6y-6= cross(6)(5/cross(6)1)(x-4)}}}

{{{6y-6= 5(x-4)}}}

{{{6y-6= 5x-20}}}

{{{6y-5x= 6-20}}}

{{{6y-5x= -14}}} to have it with a positive {{{x}}} coefficient, both sides multiply by {{{-1}}}

{{{(-1)6y-5(-1)x= -14(-1)}}}

{{{-6y+5x= 14}}}

{{{5x-6y= 14}}}