Question 86150
[3/2b] - [5/3b^3]
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The lcm = 6b^3
Rewrite each fraction with the lcm as its denominator:
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[6b^2/lcm] - [10/lcm]
Combine the numerators to get:
[6b^2-10]/6b^3
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Simplify:
[3b^2-5]/3b^3
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Cheers,
Stan H.