Question 1006389
{{{f (x)=-(1/2)^(x+2)}}}

make a table:

{{{x}}}|{{{y}}}


{{{0}}}|{{{-(1/4)}}}...{{{f (0)=-(1/2)^(0+2)}}}=>{{{f (0)=-(1/2)^2}}}=>{{{f (0)=-(1/4)}}}

{{{-4}}}|{{{-4}}}...{{{f (-4)=-(1/2)^(-4+2)}}}=>{{{f (-4)=-(1/2)^(-2)}}}=>{{{f (-4)=1/(-1/4)=-4}}}

{{{-2}}}|{{{-1}}}...{{{f (-2)=-(1/2)^(-2+2)}}}=>{{{f (-2)=-(1/2)^0}}}=>{{{f (-2)=-1}}}

{{{-1}}}|{{{-(1/2)}}}...{{{f (-1)=-(1/2)^(-1+2)}}}=>{{{f (-1)=-(1/2)^1}}}=>{{{f (-1)=-(1/2)}}}

{{{1}}}|{{{-(1/8)}}}...{{{f (1)=-(1/2)^(1+2)}}}=>{{{f (1)=-(1/2)^3}}}=>{{{f (1)=-(1/8)}}}


{{{2}}}|{{{-1/16}}}...{{{f (2)=-(1/2)^(2+2)}}}=>{{{f (2)=-(1/2)^4}}}=>{{{f (2)=-1/16}}}



plot the points:


{{{drawing( 600, 600, -10, 10, -10, 15,
circle(-2,-1,.12),circle(-1,-1/2,.12),circle(0,-1/4,.12),circle(1,-1/8,.12),circle(2,-1/16,.12),circle(-4,-4,.12),

locate(-2,-1,p(-2,-1)),locate(-1,-1/2,p(-1,-1/2)),locate(-4,-4,p(-4,-4)),
locate(0,-1/4,p(0,-1/4)),locate(1,-1/8,p(1,-1/8)),locate(-2,-1/16,p(2,-1/16)),
 graph( 600, 600, -10, 10, -10, 15, -(1/2)^(x+2))) }}}