Question 1006325
Find two numbers such that if 18 is added to the first number it becomes twice the second number and if 16 is added to the second number it becomes thrice the first number.

let x=1st number
let y=2nd number
x+18=2y
y+16=3x

2y-x=18
y-3x=-16

2y-x=18
2y-6x=-32
subtract
5x=50
x=10
y=3x-16=30-16=14

1st number=10
2nd number=14