Question 1006237
{{{(4/(x-1))>(3/x) }}}...........cross multiply

{{{4*x>3(x-1) }}}

{{{4*x>3x-3}}}

{{{4*x-3x>-3}}}

{{{x>-3}}}

since we have denominators {{{(x) }}} and {{{x-1}}}=>{{{x<>0}}} and {{{x<>1}}}

so, your solution is

{{{-3<x<0}}}=>({{{-3}}}, {{{0}}})
and {{{x>1}}}=>(1, infinity)


or ({{{-3}}}, {{{0}}}) U ({{{1}}}, {{{infinity}}})


{{{ graph( 600, 600, -10, 10, -10, 10,4/(x-1),3/x) }}}