Question 1006175
I'm assuming the given function is f(x) = 5x-4


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1)


f(x) = 5x-4
f(x+h) = 5(x+h)-4 ... replace every x with x+h
f(x+h) = 5x+5h-4


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2)


f(x) = 5x-4


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3)


f(x+h) = 5x+5h-4
f(x) = 5x-4
f(x+h)-f(x) = (5x+5h-4) - (5x-4)
f(x+h)-f(x) = 5x+5h-4 - 5x+4
f(x+h)-f(x) = (5x-5x)+5h+(-4+4)
f(x+h)-f(x) = (0x)+5h+(0)
f(x+h)-f(x) = (0)+5h+(0)
f(x+h)-f(x) = 5h


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4)

This part is blank, but I'm going to assume you meant to write {{{(f(x+h)-f(x))/h}}}



f(x+h)-f(x) = 5h


{{{(f(x+h)-f(x))/h=(5h)/h}}}


{{{(f(x+h)-f(x))/h=5}}}



So in the end, {{{(f(x+h)-f(x))/h=5}}} when {{{f(x)=5x-4}}}