Question 86125
Graph:
{{{4x+y >= 4}}} Rewrite this as: {{{y >= -4x+4}}} (Slope-intercept form)
To draw the graph, first treat this as an equation rather than an inequality:
{{{y = -4x+4}}}
{{{graph(300,200,-5,5,-5,5,-4x+4)}}}
Now, because the inequality is {{{y >= -4x+4}}} the line on the graph is a solid line (rather than dotted).
Now you need to decide which side to shade and you do this by trying a point on the left side, let's say point (0, 0) and see if this point satisfies the inequality.
{{{0 >= -4(0)+4}}}
{{{0 >= 4}}} Not, it does not!
So you shade the other side (right) of the line which then represents the area of all the solutions to this inequality.