Question 1006127
What do you really have?
y+2/3=2y-12/3y-9
Not very likely that.


{{{y+2/3=2y-12/3y-9}}}----what you WROTE if rendered.


{{{y+2/3=(2y-12)/(3y-9)}}}---------maybe what you meant.



Or is it really this?
{{{(y+2)/3=(2y-12)/(3y-9)}}}
-
{{{(y+2)(3y-9)=3(2y-12)}}}
{{{3y^2+6y-9y-18=6y-36}}}
{{{3y^2-9y-18=-36}}}
{{{y^2-3y-6=-12}}}
{{{y^2-3y+6=0}}}


{{{y=(3+- sqrt(9-4*6))/2}}}

{{{y=(3+- sqrt(-15))/2}}}

{{{highlight(y=3/2+- i*sqrt(15)/2)}}}