Question 1006066
This is still unintelligible.  Fix your question!  Are you saying you have two numbers, x and y, and that {{{y/x=3}}} ?



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Two consecutive numbers, n and n+1;
{{{n+(n+1)=16}}}
{{{2n+1=16}}}
{{{2n=15}}}
{{{n=7&1/2}}}, NOT an integer, and NOT a whole number.


You further want  {{{(n+1)/n=3}}}
{{{n+1=3n}}}
{{{1=2n}}}
{{{n=1/2}}}, unequal to the already-found value for n, and still not whole nor integer.


NO SOLUTION