Question 1006001
<font face="Times New Roman" size="+2">


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  \frac{60\ -\ 92}{45\ -\ 92}\ =\ e^{-k(43)}]


Solve for *[tex \Large k].


Once you know the value of *[tex \Large k], you can solve:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  \frac{74.5\ -\ 92}{45\ -\ 92}\ =\ e^{-kt}]


for *[tex \Large t].


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

</font>