Question 1005960
The train travels {{{ 156 }}} mi at {{{ 80 }}} mi/hr
{{{ t = 156/80 }}}
{{{ t =1.95 }}} hrs
The 30 min layover makes the time for the whole trip
is {{{ .5 + 1.95 = 2.45 }}} hrs
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making the trip at {{{ 55 }}} mi/hr:
{{{ t = 156/55 }}}
{{{ t = 2.836 }}}
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Taking the train is the quickest way
{{{ .45*60 = 27 }}}
he arrives at 8:00 + 2 hrs
 and 27 min, which is 10:27
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Going by car:
he arrives at 8:00 + 2 hrs 50.2 min,
which is 10:50 approx.