Question 1005447
Complete the square to convert to vertex form.
{{{y=(x^2+6x+9)+7-9}}}
{{{y=(x+3)^2-2}}}
So the minimum value occurs at the vertex so,
{{{y>=-2}}} or [{{{2}}},{{{infinity}}})
and the domain is all real numbers ({{{-infinity}}},{{{infinity}}})
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*[illustration des4.JPG].