Question 1005854
since slope (f'(x)) = 2x + 1
f(x) = x^2 +x + c where c is a constant
now f(x) goes through point (1, -4), then
-4 = 1^2 + 1 + c and c = -6
f(x) = x^2 + x - 6
to find x intercepts set f(x) = 0 and solve for x
x^2 + x -6 = 0
factor polynomial
(x+3) * (x-2) = 0
x intercepts are -3, 2