Question 86088
a. D = 10log{{{I/Io}}}
b. D1 = 10log{{{I1/Io}}}
   D2 = 10log{{{100I1/Io}}} = 10(log 100I1 - log Io) = 10(log 100 + log I1 - log Io) = 10(2 + log I1 - log Io) = 20 + 10{{{log I1/log Io}}} ; 20 decibels greater.