Question 1005855
Find two numbers such that if 18 is added to the first number it becomes twice the second number and 16 is added to the second number it becomes three times the first number
let number first is X 
than second number will be   y 
X+18= 2y
x-2y=-18 (1)
y+16=3x
3x-y=16 (2)   by solving both equations  3x-6y=-54  and 3x-y=16
5y=70   y=14   x= 10
answer first number is 10