Question 1005740
{{{ -ln(1/13)/(2) }}} simplified to {{{ ln(13)/2 }}}:


{{{ -ln(1/13)/2 }}}


{{{ -((ln(1)-ln(13)))/2 }}}


{{{ -ln(1)/2+ln(13)/2 }}}........since {{{ln(1)=0}}}, we have

{{{ -0/2+ln(13)/2 }}}

{{{ ln(13)/2 }}}