Question 1005723

{{{log(7,0)=x}}} (I guess you have base {{{7}}})rewritten its ({{{7^x=0 }}}

recall: {{{log(b,(y)) = x}}}  is equivalent to (means the exact same thing as) {{{y = b^x}}}

in your case  base is {{{b=7}}}, {{{y=0}}}, and {{{x=x}}}