Question 1005610
roots are -1 and +/- 2i, because complex roots are conjugate.  This is a cubic equation.
the factors are (x+1) and (x^2+4), since x^2+4=0, and the roots are +/- 2i
the polynomial is x^3+x^2+4x+4=f(x)
{{{graph(300,200,-10,10,-10,10,x^3+x^2+4x+4)}}}