Question 1005505
Hi dear,
Follow the step below.
 log2(x²-11)-log2(2x+5)=1
Then,
apply law of logarith.
log2[(x²-11)/(2x+5)]=1
but
log2[(x²-11)/(2x+5)=log2 base 2
cancel log from bothside,
(x²-11)/(2x+5)=2
Then,simplify out,
x²-11=2(2x+5)
x²-11=4x+10
x²-4x-21=0
factorize,
(x²-7x)+(3x-21)=0
x(x-7)+3(x-7)=0
(x+3)(x-7)=0
x+3=0  or x-7=0
x=-3  or x=7
Therefore the value of x is -3 or 7.
HOPE THIS HELPS?
::TIMNEWMAN::