Question 1005504
{{{log((x(x-5)))=log((3x-15))}}}


The antilogs must be equal.
{{{x^2-5x=3x-15}}}
{{{x^2-5x-3x+15=0}}}
{{{x^2-8x+15=0}}}
{{{(x-3)(x-5)=0}}}


x is 3 or x is 5.