Question 1005497
{{{x+2y=-2}}}
{{{2y=-x-2}}}
{{{y=-(1/2)x-1}}}


The slope for a line perpendicular to that one is  negative reciprocal of {{{-1/2}}}, which is  {{{2}}}.


FINDING VERTICAL AXIS INTERCEPT
{{{y=mx+b}}}
{{{y-mx=b}}}
{{{b=y-mx}}}


The line you want in slope-intercept form, but before final simplification is {{{y=2x+(-4-2(-3))}}}