Question 1005463
note when dropping an object from height, the initial velocity vo is 0.  G is 16 for this problem, since given values are in feet.
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1a) h(3) = -8*3^2 + 0*3 + 1250 = 1178
after 3 seconds, the penny is 1178 feet above the ground
1b) 0 = -8t^2 +1250
t^2 = 156.25 and t = 12.5
after 12.5 seconds, the penny hits the ground
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the height of the building is given in feet, so convert vo = 10 m to feet/s, vo = 32.8 feet
2a) h(3) = -8*3^2 + 32.8*3 + 495 = 521.4
after three seconds, the ball is 521.4 feet above the ground.
2b) 0 = -8t^2 + 32.8t + 495
t^2 -4.1t - 61.875 = 0
t^2 -4.1t = 61.875
t^2 -4.1t + 4.2025 = 4.2025 + 61.875
(t - 2.05)^2 = 66.0775
t - 2.05 = 8.128806801 = approx 10.2 
in 10.2 seconds the ball hits the ground
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here is the graph of 2b
{{{graph(300, 200, -10, 12, -2, 800, -8x^2 +32.8x +495)}}}