Question 1005270
Solution XRD is one half sulfur acid while QXJ is 3/4 sulfur acid. How many liters of solution QXJ should be added to a liter of solution XRD to obtain a solution that is 3/5 sulfur acid?
<pre>Let amount of QXJ solution to add, be q
It's best to change the fractions to decimals. 
In so doing, {{{1/2}}} becomes: .5; {{{3/4}}} becomes: .75, {{{3/5}}} becomes .6, and we get: 
.5(1) + .75(q) = .6(1 + q)
.5 + .75q = .6 + .6q
.75q - .6q = .6 - .5 
.15q = - .1
q, or amount of QXJ solution to add = .1/.15, or {{{highlight_green(2/3)}}} L