Question 1005281
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1.  a/2x + 6a = -bx + 4


First multiply both sides by  2  to get rid of denominators:


ax + 12a = -2bx + 8.


Now,  collect all terms with x on the left side,  and all other terms on the right side. 

When you move the terms between the sides,  change their signs for opposites.


ax + 2bx = 8 - 12a.

(a + 2b)x = 8 - 12a.


Next,  divide both sides by  (a + 2b)  assuming it is not the zero:


x = {{{(8-12a)/(a+2b)}}}.


That's all.



2. Now,  do the same with the second equation.


I don't want to deprive you a pleasure to make it yourself :)