<PRE><B>Question 1005305</B>
&lt;TABLE&gt; 
  &lt;TR&gt;
  &lt;TD&gt; 

{{{graph( 330, 330, -3.5, 5.5, -2.5, 8.5,
           abs(x^2-2x),
           abs(3x-6)
)}}}


&lt;B&gt;Figure&lt;/B&gt;. Plots &amp;nbsp;|x^2-2x| &amp;nbsp;and &amp;nbsp;|3x-6| 

  &lt;/TD&gt;
  &lt;/TR&gt;
&lt;/TABLE&gt;

You need to consider the given equation on three separate intervals/segment: 


1) x &lt; 0,

2) 0 &lt;= x &lt;= 2, &amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;and

3) x &gt; 2.


On the first interval your equation becomes


{{{x^2-2x = -3x + 6}}}.


On the second interval your equation becomes


{{{-x^2+2x = -3x + 6}}}.


On the third interval your equation becomes


{{{x^2-2x = 3x - 6}}}.


Now solve each equation in its interval.


</PRE>