Question 1005260
w and L dimensions.
{{{2w+2L=20}}}, wL is the initial area.


{{{(L+2)(w+3)-wL=30}}}
{{{wL+2w+3L+6-wL=30}}}
{{{2w+3L=30}}}


Perimeter equation for the initial rectangle simplifies to {{{w+L=10}}}.


Solve this system for L and w:
{{{system(2w+3L=30,w+L=10)}}}.