Question 1005059
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Three medians of a triangle  (of any triangle!)  intersect in one common point. 
It is very well known property of medians of a triangle.


In other words,  three medians of a triangle are concurrent. 
Regarding this property, &nbsp;see, &nbsp;for example the lesson &nbsp;<A HREF=http://www.algebra.com/algebra/homework/Triangles/Medians-of-a-triangle-are-concurrent.lesson>Medians of a triangle are concurrent</A>&nbsp; in this site.


It is known fact also that the intersection point divides each median in proportion &nbsp;2:1 &nbsp;counting 

from the corresponding vertex to the opposite side. 


So, &nbsp;your problem is talking about the intersection point of the medians of the given triangle.


This point has one more remarkable property/feature: &nbsp;it is the centroid, &nbsp;or the center of mass of a triangle. 

Its coordinates are 


{{{x[centr]}}} = {{{(x[A] + x[B] + x[C])/3}}},


{{{y[centr]}}} = {{{(y[A] + y[B] + y[C])/3}}},


where &nbsp;x{A], &nbsp;x[B] and &nbsp;x[C] &nbsp;are &nbsp;x-coordinates of the triangle vertices, &nbsp;while &nbsp;y{A], &nbsp;y[B] &nbsp;and &nbsp;y[C] &nbsp;are their &nbsp;y-coordinates.


See the lesson &nbsp;<A HREF=http://www.algebra.com/algebra/homework/word/geometry/The-Centroid-of-a-triangle-is-the-Intersection-point-of-its-medians.lesson>The Centroid of a triangle is the Intersection point of its medians</A>&nbsp; in this site.


So, &nbsp;for the given triangle 


{{{x[centr]}}} = {{{(4 + 10 + 2)/3}}} = {{{16/3}}},


{{{y[centr]}}} = {{{((-4) + 4 + 6)/3}}} = {{{2}}}.