Question 1004957
The vertex has a value for x which is exactly in the middle of the zeros of the function.



Let D be the discriminant.
Zeros of x are  {{{(6+- sqrt(D))/2}}}.
Find the value of x in the middle.



{{{(1/2)((6-sqrt(D))/2+(6+sqrt(D))/2)}}}


{{{(1/2)(1/2)(6-sqrt(D)+6+sqrt(D))}}}


{{{(1/4)12}}}


{{{highlight(3)}}}--------the x value for the vertex.



Now, knowing that, what is g(3)?
Vertex point will be   (3,g(3)).