Question 85985
x=2y
y=x-2
Use the substitution method to solve:
y=x-2 [substitute (x=2y) for the "x" term and solve]
y=(2y)-2
y=2y-2
0=2y-y-2
0=y-2
2=y [plug (y=2) back into either equation and solve for the x-term]
.
x-2y
x=2(2)
x=4
.
checking:
y=x-2
2=4-2
2=2 [checks out]
.
So, the solution is (4, 2) as a common, intersecting point for both of these lines.

{{{ graph( 300, 200, -6, 5, -10, 10, (1/2)x, x-2) }}}