Question 1004975
Use the general rule:
{{{ a^(-b) = 1/(a^b) }}}
{{{ a = 16 }}}
{{{ b = 1/2 }}}
--------------
{{{ 16^(-1/2) = 1/((16^(1/2))) }}}
{{{ 1/16^(1/2) = 1/(( 4^2 )^(1/2)) }}}
-------------------
Now use the general rule:
{{{ ( a^b )^c = a^(b*c) }}}
{{{ 1/(( 4^2 )^(1/2)) = 1/(( 4^(2/2))) }}}
{{{ 1/( 4^(2/2)) = 1/4 }}}