<PRE><B>Question 1004980</B>
How many liters of 10% alcohol solution and 5% alcohol solution must be mixed to get 40 liters of 8%?
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Equation:
alcohol + alcohol = alcohol
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0.10x + 0.05(40-x) = 0.08*40
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10x + 5*40 - 5x = 8*40
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5x = 3*40
x = 24 liters (amt. of 10% solution needed)
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40-x = 16 liters (amt. of 5% solution needed)
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Cheers,
Stan H.
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