Question 1004909
Using the laws of exponents
log3(2x-3)-log3(x+2)=3
becomes
log(3) ((2x-3)/(x+2)) = 3
Now exponentiate 3-to-the and get
(2x-3)/(x+2) = 27
Now multiply by x+2 and solve
2x - 3 = 27x + 54
-57 = 25x
x = -57/25