Question 86010
First, I would take the given equation and square the binomial:
{{{(1/a+a)^2=144}}}
{{{1/a^2+2+a^2=144}}}
Now, just solve for the expression {{{1/a^2+a^2}}}:
{{{highlight(1/a^2+a^2=142)}}}
Good Luck,
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