Question 86005
Almost!
Divide:
{{{((x^2+2x-15)/4x^2)/((x^2-25)/(2x-10))}}} Invert the 2nd fraction and multiply.
{{{((x^2+2x-15)/4x^2)((2x-10)/(x^2-25)))}}} Factor the numerators and denominators where possible.
{{{((x-3)cross((x+5))/4x^2)(2cross((x-5))/cross((x-5))cross((x+5)))}}} Cancel the like-factors as indicated leaving you with:
{{{2(x-3)/4x^2}}} Cancel 2's
{{{(x-3)/2x^2}}}
Notice that in your answer, the numerator has the opposite sign but was otherwise correct!