Question 1004833
given:

The vertices of a triangle are:
 A ({{{4}}},{{{-4}}}), B ({{{10}}},{{{4}}}) and C ({{{2}}},{{{6}}})

plot the points and draw a triangle:

{{{drawing( 600, 600, -15, 15, -10, 15,
circle(4,-4,.12),circle(10,4,.12),circle(2,6,.12),
locate(4,-4,A(4,-4)),locate(10,4,B(10,4)),locate(2,6,C(2,6)),
line(4,-4,10,4),line(4,-4,2,6),line(2,6,10,4),
 graph( 600, 600, -15, 15, -10, 15, 0)) }}}

if the vertex {{{C}}}, the opposite side is {{{AB}}}

so, find the midpoint of the opposite side {{{AB}}}

*[invoke midpoint 4, -4, 10, 4] 


the midpoint is at ({{{7}}},{{{0}}}) and C is at ({{{2}}},{{{6}}})

find the distance between these two points:


*[invoke distance_formula 7, 0, 2, 6]