Question 1004862
Find the lengths of the sides of the triangle with the vertices A(-2,-3), B(6,1) & C (-2,-5)
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Use the distance formula:
{{{d = sqrt(diffy^2 + diffx^2)}}}
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For AB:
{{{d = sqrt((-3-1)^2 + (-2-6)^2) = sqrt(16 + 64)}}}
{{{AB = 4sqrt(5)}}}
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Do the others the same way.