Question 85991
{{{16x^4 - 1}}}
This is a difference of squares
eg {{{(4x^2)^2 - 1^2}}}
So factorise it
{{{(4x^2-1)(4x^2+1)}}}
The first term is still a difference of squares
eg {{{((2x)^2-1^2)(4x^2+1)}}}
so factorise it
{{{(2x-1)(2x+1)(4x^2+1)}}}