Question 1004731

{{{(sqrt(3) +i)(sqrt(3) -i)}}}.......recall the difference of squares {{{a^2-b^2=(a+b)(a-b)}}}

so, you have 
{{{(sqrt(3) +i)(sqrt(3) -i)=(sqrt(3))^2 -i^2=3-(-1)=3+1=4}}}