Question 85983
{{{1^3  = (1)^2}}}
{{{1^3 + 2^3 = (1+2)^2}}}
{{{1^3 + 2^3 + 3^3  = (1+2+3)^2}}}
{{{1^3 + 2^3 + 3^3 + 4^3 = (1+2+3+4)^2}}}

Your pattern appears to be 
The sum of n base numbers cubed = (sum the base numbers) then square the result.

This would give a result
sum of the cubes of the first ten natural numbers = {{{(1+2+3+4+5+6+7+8+9+10)^2=55^2}}}
=3025