<PRE><B>Question 1004575</B>
Our half-life formula is
G(t) = Ao * (1/2)^(t/h), where h is the half-life and A0 is the beginning amount
16 = 256 * (1/2)^(105/h)
1/16 = (1/2)^(105/h)
use definition of logarithm
105/h = log (base 1/2) of 1/16
105/h = 4
h = 105/4 = 26.25 minutes
half-life is 26.25 minutes
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we use our formula for t = 17
G(17) = 256 * (1/2)^(17/26.25)
G(17) = 163.413226968 approx 163.4
There is 163.4 grams of goo after 17 minutes
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