Question 1004575
{{{G=256*e^(-kt)}}} decay model


{{{ln(G)=ln(256)-kt}}}
{{{ln(G)-ln(256)=-kt}}}
{{{highlight_green(kt=ln(256)-ln(G))}}}
{{{k=(1/t)ln(256/G)}}}
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{{{k=(1/105)(ln(256/16))}}}
{{{highlight(k=0.02641)}}} based on minutes and grams


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HALF-LIFE
{{{t=ln(256/128)/0.02641}}}
{{{highlight(t=26.25*minutes)}}}


Use the model as {{{G=256*e^(-0.02641*t)}}}  for t=17 to find how much remains after that amount of time.