<PRE><B>Question 1004450</B>
The sum of the areas of two squares is 89 square centimeters. The length of a side of the larger square is 3 centimeters more than the length of a side of the smaller square. Find the dimensions of each square. 


the length of a side of the smaller square.   let it be x

Area = x^2


The length of a side of the larger square is 3 centimeters more than .(x+3)
area = (x+3)^2

The sum of the areas of two squares is 89 square centimeters. 

x^2+(x+3)^2=89

x^2+x^2+6x+9 = 89

2x^2+6x-80=0

/2
x^2+3x-40=0

x^2+8x-5x-40=0

x(x+8)-5(x+8)=0
(x+8)(x-5)=0
x=-8 OR x= 5
Ignore negative
dimensions of the squares are

5 by 5 cm and 8 by 8 cm
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