Question 1004382
Hi there,
Three consecutive integers.
n + (n + 1) + (n + 2)
the sum of the largest and 5 times the smallest is -244.
(n + 2) + 5(n) = -244
n + 2 + 5n + -244
Collect like terms
n + 5n = -244 - 2
6n = -246
n = -41
Three consecutive integers
-41, -40, -39.
the sum of the largest and 5 times the smallest is -244.
-39 + 5(-41) = -244
-39 + -205 = -244
Hope this helps :-)