<PRE><B>Question 85902</B>
let x = the number
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The difference of twice a number and five is equal to the square of the difference of the number and fifteen. 
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2x - 5 = (x-15)^2
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What is the number?
2x - 5 = x^2 - 30x + 225; FOILed (x-15)*(x-15)
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0 = x^2 - 30x - 2x + 225 + 5
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x^2 - 32x + 230 = 0
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I  would think that a solution would be an integer, but it&#39;s not the case here.
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Using the quadratic formula I got solutions of +10.90098 and 21.09902 
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Both of these values do satisfy the equation

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