Question 1004328
log7(8x)=log7(2x)+log7(3x-5)
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log7(8x) = log7[2x(3x-5)]
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8x = 6x^2-10x
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6x^2 - 18x = 0
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6x(x-3) = 0
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x = 0 or x = 3
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Acceptable answer:: x = 3
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Cheers,
Stan H.