Question 1004239
That ratio is also 1:2.
Let x,y,z be the lengths of each side for the small triangle.  The altitude is also in the same ratio between the two triangles (because linear measures).


Small perimeter, x+y+z
Large perimeter, 2(x+y+z)
If h is the altitude of the small triangle, the 2h is altitude for large triangle.


Small area, {{{(1/2)zh}}}
large area, {{{(1/2)2z*2h=(1/2)*4*zh}}}


Their summed areas is {{{100=(1/2)zh+(1/2)*4zh}}}
{{{200=zh+4zh=5zh}}}
{{{zh=200/5}}}
{{{zh=40}}}
This can now be used for finding the value of each area.


Small Triangle,  {{{(1/2)*40=highlight(20)}}}
Large Triangle, {{{(1/2)*4*zh=2*40=highlight(80)}}}