Question 1004229
{{{y+3= sqrt((x/16)(+2))}}}
{{{y+3= sqrt((x/16)(2))}}}
{{{y+3=sqrt(2(x/16))}}}
{{{y+3=(1/4)sqrt(2x)}}}
{{{y+3(4/4)=(1/4)sqrt(2x)}}}

{{{y=(1/4)sqrt(2x)-(3*4)/4}}}
{{{y=(1/4)(sqrt(2x)-12)}}}
Almost in the form you want.  The only question is how you expect to compare 2x and x-h.


Maybe,  {{{2x=x-h}}}
{{{2x-x=-h}}}
{{{x-2x=h}}}
{{{h=-x}}}


Maybe you should give the exact problem description.