<PRE><B>Question 1004187</B>
L+W=34 (half the perimeter)
L=34-W
Pythagorean theorem
W^2+(34-W)^2=26^2
W^2+W^2-68W+1156=676; 2W^2-68W+480=0
2(W^2-34W+240)=0,  factoring 2.
(W-24)(W-10)=0
W=24 or 10.  One is length, 24 cm, the other width, 10 cm.
The perimeter is 68 cm.
The square of 24 (576) and 10 (100)= square of diagonal, 26, cm, (676)</PRE>